document.write( "Question 235770: members of a hiking club hiked to an overnight campsite at the rate of 3 mph. The following morning they returned on horseback over the same route at 10 mph. The total time spent in going and returning was 6 1/2 hrs. find the distance to the campsite.\r
\n" ); document.write( "\n" ); document.write( "I know d= r x t, but don't know what to use for rate. 3 mph or 10 mph?
\n" ); document.write( "

Algebra.Com's Answer #173579 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
members of a hiking club hiked to an overnight campsite at the rate of 3 mph. The following morning they returned on horseback over the same route at 10 mph. The total time spent in going and returning was 6 1/2 hrs. find the distance to the campsite.
\n" ); document.write( "---------------
\n" ); document.write( "Hiking DATA:
\n" ); document.write( "rate = 3 mph ; distance = x miles ; time = d/r = x/3 hrs
\n" ); document.write( "=======================
\n" ); document.write( "Riding DATA:
\n" ); document.write( "rate = 10 mph ; distance = x miles ; time = x/10 hrs
\n" ); document.write( "-----------------------
\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 13/2 hrs
\n" ); document.write( "x/3 + x/10 = 13/2
\n" ); document.write( "Multiply thru by 30 to get:
\n" ); document.write( "10x + 3x = 15*13
\n" ); document.write( "13x = 15*13
\n" ); document.write( "x = 15 miles (distance to the campsite)
\n" ); document.write( "========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );