document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235722>Question 235722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a blend of coffee has 60% of grade A and 40% of grade B, and is sold at 78 cents a pound. If the blend was 40% grade A and 60% grade B, the price would be 62 cents a pound. find the price of grade A per pound </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173551 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a blend of coffee has 60% of grade A and 40% of grade B, and is sold at 78 cents a pound.<BR>\n" );
document.write( " If the blend was 40% grade A and 60% grade B, the price would be 62 cents a pound. <BR>\n" );
document.write( "find the price of grade A per pound<BR>\n" );
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document.write( "Let A = cost of Grade A per pound (in cents)<BR>\n" );
document.write( "Let B = cost of Grade B per pound<BR>\n" );
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document.write( "Write an equation for each blend<BR>\n" );
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document.write( ".6A + .4B = 78<BR>\n" );
document.write( ".4A + .6B = 62<BR>\n" );
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document.write( "Multiply the 1st equation by 3, multiply the 2nd equation by 2<BR>\n" );
document.write( "1.8A + 1.2B = 234<BR>\n" );
document.write( "0.8A + 1.2B = 124<BR>\n" );
document.write( "---------------------Subtraction eliminates B, find A<BR>\n" );
document.write( "1A + 0 = 110<BR>\n" );
document.write( "A = 110 cents or $1.10 a lb<BR>\n" );
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document.write( "To check our solution, find the cost of B<BR>\n" );
document.write( ".6(110) + .4B = 78<BR>\n" );
document.write( "66 + .4B = 78<BR>\n" );
document.write( ".4B = 78 - 66<BR>\n" );
document.write( ".4B = 12<BR>\n" );
document.write( "B = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2F.4 ALIGN=MIDDLE  ALT=\"12%2F.4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "B = 30 cents a lb<BR>\n" );
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document.write( "Check this in the 2nd equation<BR>\n" );
document.write( ".4(110) + .6(30) =<BR>\n" );
document.write( "44 + 18 = 62; confirms our solution </SPAN>\n" );
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