document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30623>Question 30623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a right triangle, if the length of the hypotenuse is 6 and one side is x. How large could x be to maximize the area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17352 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a right triangle, if the length of the hypotenuse is 6 and one side is x. How large could x be to maximize the area.<BR>\n" );
document.write( "USING PYTOGARUS THEOREM <BR>\n" );
document.write( "OTHER LEG =SQUARE ROOT OF (6^2-X^2)=SQRT.(36-X^2)<BR>\n" );
document.write( "AREA = (1/2)*(X)*SQRT.(36-X^2)<BR>\n" );
document.write( "SQUARING AREA WILL BE MAXIMUM WHEN<BR>\n" );
document.write( " Y= X^2(36-X^2) IS MAXIMUM...PUT P=X^2........<BR>\n" );
document.write( "Y=P(36-P)=36P-P^2 SHALL BE MAXIMUM<BR>\n" );
document.write( "=-{P^2-2*P*18+18^2-18^2)=18^2-(P-18)^2...SHALL BE MAXIMUM..THAT HAPPENS WHEN <BR>\n" );
document.write( "(P-18)=0...OR....P=18=X^2...OR X=SQRT(18)=3*SQRT.(2)=3*1.41=4.23<BR>\n" );
document.write( " </SPAN>\n" );
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