document.write( "Question 235546: a manufacture of tv tubes has for many years used a process giving a mean tube life of 4900 hrs and a standard deviation of 1200 hours.
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document.write( "A new process is tried to see if it will increase the life significantly. A sample of 100 new tubes gave a mean life of 5000 hrs. Is the new process better than the old process at 1% level of significant? Construct hypotheses test it and interpret the result. \n" );
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Algebra.Com's Answer #173515 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a manufacture of tv tubes has for many years used a process giving a mean tube life of 4900 hrs and a standard deviation of 1200 hours. \n" ); document.write( "-------------------------------------------------------------------- \n" ); document.write( "A new process is tried to see if it will increase the life significantly. \n" ); document.write( "A sample of 100 new tubes gave a mean life of 5000 hrs. \n" ); document.write( "-------------------------------------------------------------------- \n" ); document.write( "Is the new process better than the old process at 1% level of significant? Construct hypotheses test it and interpret the result. \n" ); document.write( "--------------------- \n" ); document.write( "Ho: u = 4900 \n" ); document.write( "Ha: u > 4900 (claim) \n" ); document.write( "------------------------- \n" ); document.write( "Test statistic: t(5000) = (5000-4900)/[1200/Sqrt(100)] =1000/1200= 0.8333.. \n" ); document.write( "------------------------------- \n" ); document.write( "p-value: P(t>0.8333 with df=99) = 0.2033 \n" ); document.write( "--------------------------------- \n" ); document.write( "Since the p-value is greater than 1% do not reject Ho. \n" ); document.write( "The new process is not an improvement over the old process. \n" ); document.write( "============================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |