document.write( "Question 235627: can u please explain the logarithm 3log2x-log2x=8? by the way the log has a base of 2. the book said that the answer was 8.1 but i dont understand how they got that. this is wat i did:
\n" ); document.write( "3log2x-log2x=8
\n" ); document.write( " $\"log2x%5E3-log2x=8\"$
\n" ); document.write( " $\"log2%28x%5E3%2Fx%29=8\"$
\n" ); document.write( " $\"2%5E8=x%5E3%2Fx\"$
\n" ); document.write( " $\"256=x%5E3%2Fx\"$
\n" ); document.write( "
\n" ); document.write( "and thats as far as i got \n" ); document.write( "

Algebra.Com's Answer #173492 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
3log2x-log2x=8
\n" ); document.write( " $\"log%282%2Cx%5E3%29-log%282%2Cx%29=8\"$
\n" ); document.write( " $\"log%282%2C%28x%5E3%2Fx%29%29=8\"$
\n" ); document.write( " $\"2%5E8=x%5E3%2Fx\"$
\n" ); document.write( " $\"256=x%5E3%2Fx\"$
\n" ); document.write( "and thats as far as i got
\n" ); document.write( " $\"256+=+x%5E2\"$
\n" ); document.write( "x = ą16
\n" ); document.write( "Since it's inside the log function, the -16 is rejected.
\n" ); document.write( "--------
\n" ); document.write( "You were almost there.
\n" ); document.write( "I don't see how it can be 8, unless there's a typo. \n" ); document.write( "

\n" );