document.write( "Question 235480: A man did a job for $360. It took him 6 hours longer than he expected and therefore he earned $2 per hour less than he anticipated. How long did he expect that it would take to do the job? \n" ); document.write( "
Algebra.Com's Answer #173453 by stanbon(75887)\"\" \"About 
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A man did a job for $360. It took him 6 hours longer than he expected and therefore he earned $2 per hour less than he anticipated. How long did he expect that it would take to do the job?
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\n" ); document.write( "Let the time he expected to use be \"x\" hrs.
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\n" ); document.write( "He received 360/(x+6) dollars per hour.
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\n" ); document.write( "He expected to make 360/x dollars per hour
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\n" ); document.write( "Equation:
\n" ); document.write( "Expected rate - received rate = 2 dollars
\n" ); document.write( "360/x - 360/(x+6) = 2
\n" ); document.write( "Multiply thru by x(x+6) to get:
\n" ); document.write( "360(x+6) - 360x = 2x(x+6)
\n" ); document.write( "2x^2 + 12x - 360*6 = 0
\n" ); document.write( "x^2 + 6x - 1080 = 0
\n" ); document.write( "(x-30)(x+36) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 30 hrs (amount of time he expected to work to do the job)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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