document.write( "Question 30617: solve each compound ineqaulity and write the solution set using interval notation.
\n" ); document.write( "-3<(3x-1)/5<1/2 and 1/3<(3-2x)/6<9/2
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Algebra.Com's Answer #17345 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+-3%3C%283x-1%29%2F5%3C1%2F2+\" and \"+1%2F3%3C%283-2x%29%2F6%3C9%2F2+\"
\n" ); document.write( "We will solve these one at a time. As these are compound inequalities, like an equation where if you add 5 to each side .... here you do it to all three parts of the inequality.
\n" ); document.write( "\"+-3%3C%283x-1%29%2F5%3C1%2F2+\" Multiply by 5
\n" ); document.write( "\"+-15%3C3x-1%3C5%2F2+\" Add 1
\n" ); document.write( "\"+-14%3C3x%3C7%2F2+\" divide by 3
\n" ); document.write( "\"+-14%2F3%3Cx%3C7%2F6+\" the smaller value is on the left, the larger on the right, and the <> symbols are pointing left. If you need to reduce the fractions to mixed numbers, do so now.
\n" ); document.write( "\"+1%2F3%3C%283-2x%29%2F6%3C9%2F2+\" Multiply by 6
\n" ); document.write( "\"+6%2F3%3C3-2x%3C54%2F2+\" reduce the fractions now
\n" ); document.write( "\"+2%3C3-2x%3C27+\" subtract 3
\n" ); document.write( "\"+-1%3C-2x%3C24+\" Divide by negative 2
\n" ); document.write( "DONT FORGET TO FLIP THE < > SYMBOL WHEN * OR / BY A NEGATIVE!!!!
\n" ); document.write( "\"+1%2F2%3Ex%3E-12+\" Smaller number needs to be on the left ... flip the WHOLE thing end for end
\n" ); document.write( "\"+-12%3Cx%3C1%2F2+\"\r
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