document.write( "Question 235211: trains a andb are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a. \n" ); document.write( "

Algebra.Com's Answer #173448 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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trains a and b are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a.
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\n" ); document.write( "from the given information, we know that train B is 12 min (.2 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .2 * 100 = 20 mi
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\n" ); document.write( "Let t = time required for train B to catch train a
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train b travel dist = Train a travel dist + 20 mi
\n" ); document.write( "100t = 80t + 20
\n" ); document.write( "100t - 80t = 20
\n" ); document.write( "20t = $\"20%2F20\"$
\n" ); document.write( "t = 1 hr
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\n" ); document.write( "3:10 + 1:00 = 4:10 pm, B catches A
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\n" ); document.write( "Check solution by finding the distances (train b travels 20 mi more than train b)
\n" ); document.write( "100 * 1 = 100 mi
\n" ); document.write( " 80 * 1 = 80 mi
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\n" ); document.write( "difference = 20 mi
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