document.write( "Question 235469: The width of a rectangle is 3 feet less than its length. If the perimeter is 22 feet, what is the width? \r
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Algebra.Com's Answer #173428 by Stitch(470)\"\" \"About 
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The perimeter of a rectangle equals 2L + 2W
\n" ); document.write( "Equation 1: \"P+=+2%2AL+%2B+2%2AW\"
\n" ); document.write( "Equation 2: \"W+=+L+-+3\"
\n" ); document.write( "Given: P = 22\r
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\n" ); document.write( "Plug (L - 3) into equation 1 for W, and 22 for P
\n" ); document.write( "\"P+=+2%2AL+%2B+2%2AW\"
\n" ); document.write( "\"22+=+2%2AL+%2B+2%2A%28L+-+3%29\" Rewrite the equation
\n" ); document.write( "\"22+=+2%2AL+%2B+2%2AL+-+6\" Combine like terms
\n" ); document.write( "\"22+=+4%2AL+-+6\" Add 6 to both sides
\n" ); document.write( "\"28+=+4%2AL\" Divide both sides by 4
\n" ); document.write( "\"7ft+=+L\"\r
\n" ); document.write( "\n" ); document.write( "Now plug the 7ft into equation 2 for L
\n" ); document.write( "\"W+=+L+-+3\"
\n" ); document.write( "\"W+=+7+-+3\"
\n" ); document.write( "\"W+=+4ft\"
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\n" ); document.write( "Check your answer using the values in equation 1
\n" ); document.write( "\"P+=+2%2AL+%2B+2%2AW\"
\n" ); document.write( "\"22+=+2%2A7+%2B+2%2A4\"
\n" ); document.write( "\"22+=+14+%2B+8\"
\n" ); document.write( "\"22+=+22\"
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