document.write( "Question 30336: Question:
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document.write( "How many real solutions does this nonlinear system have?
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document.write( "x^2+y2=13
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document.write( "=x^2+2y^2=14\r
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document.write( "(a) 0
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document.write( "(b) 1
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document.write( "(c) 2
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document.write( "(d) 3
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document.write( "(e) 4 \n" );
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Algebra.Com's Answer #17341 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! x^2+y2=13 ----(1) \n" ); document.write( "x^2+2y^2=14 ----(2) \n" ); document.write( "That is (x^2+y^2)+y^2 = 14 ----(2) \n" ); document.write( "putting (1) in (2) \n" ); document.write( "13+y^2 =14 \n" ); document.write( "y^2 = 14-13 \n" ); document.write( "y^2 =1 \n" ); document.write( "y = +1 or y = -1 for which we get x^2 = 12 \n" ); document.write( "And x^2 = 12 implies x = +sqrt(12) and x = -sqrt(12) \n" ); document.write( "Therefore there are four solutions \n" ); document.write( "which is your choice (e) 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |