document.write( "Question 30336: Question:
\n" ); document.write( "How many real solutions does this nonlinear system have?
\n" ); document.write( "x^2+y2=13
\n" ); document.write( "=x^2+2y^2=14\r
\n" ); document.write( "\n" ); document.write( "(a) 0
\n" ); document.write( "(b) 1
\n" ); document.write( "(c) 2
\n" ); document.write( "(d) 3
\n" ); document.write( "(e) 4
\n" ); document.write( "

Algebra.Com's Answer #17341 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
x^2+y2=13 ----(1)
\n" ); document.write( "x^2+2y^2=14 ----(2)
\n" ); document.write( "That is (x^2+y^2)+y^2 = 14 ----(2)
\n" ); document.write( "putting (1) in (2)
\n" ); document.write( "13+y^2 =14
\n" ); document.write( "y^2 = 14-13
\n" ); document.write( "y^2 =1
\n" ); document.write( "y = +1 or y = -1 for which we get x^2 = 12
\n" ); document.write( "And x^2 = 12 implies x = +sqrt(12) and x = -sqrt(12)
\n" ); document.write( "Therefore there are four solutions
\n" ); document.write( "which is your choice (e) 4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );