document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235390>Question 235390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains a and b are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173403 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> trains a and b are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 100 miles per hour. train a passes a station at 3:10 pm. If train B passes the same station at 3:22 pm at what time will train b catch up to a. \r<BR>\n" );
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document.write( "In the 12 mins from 310 to 322, train a goes 16 miles (80 * 1/5 hour)<BR>\n" );
document.write( "Train B gains on train A at 20 mph (100 - 80)<BR>\n" );
document.write( "16/20 = 4/5 hours = 48 minutes<BR>\n" );
document.write( "322 + 48 = 4:10 PM<BR>\n" );
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