document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235396>Question 235396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there is a similar question on here but it doesnt show how to solve it. <BR>\n" );
document.write( "The perimeter of a rectangle yard is 270 feet. If its length is 25 feet greater than its width what are the dimensions of the yard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173402 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+25<BR>\n" );
document.write( "2L+2W=270<BR>\n" );
document.write( "2(W+25)+2W=270<BR>\n" );
document.write( "2W+50+2W=270<BR>\n" );
document.write( "4W=270-50<BR>\n" );
document.write( "4W=220<BR>\n" );
document.write( "W=220/4<BR>\n" );
document.write( "W=55 THE WIDTH.<BR>\n" );
document.write( "L=55+25=80 THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*80+2^55=270<BR>\n" );
document.write( "160+110=270<BR>\n" );
document.write( "270=270 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );