document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235405>Question 235405</A>: <I><SPAN STYLE=\"word-break: break-all;\"> here is the problem : Find three consecutive integers such that the sum of the squares of the second and third exceeds the square of the first by 77. please!!thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173396 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+1 & x+2 be the 3 integers.<BR>\n" );
document.write( "(x+1)^2+(x+2)^2=x^2+77<BR>\n" );
document.write( "x^2+2x+1+x^2+4x+4=x^2+77<BR>\n" );
document.write( "2x^2-x^2+6x+5-77=0<BR>\n" );
document.write( "x^2+6x-72=0<BR>\n" );
document.write( "(x+12)(x-6)=0<BR>\n" );
document.write( "x+12=0<BR>\n" );
document.write( "x=-12 ans.<BR>\n" );
document.write( "x-6=0<BR>\n" );
document.write( "x=6 ans.<BR>\n" );
document.write( "Proofs:<BR>\n" );
document.write( "(-12+1)^2+-12+2)^2=-12^2+77<BR>\n" );
document.write( "-11^2+-10^2=144+77<BR>\n" );
document.write( "121+100=221<BR>\n" );
document.write( "221=221<BR>\n" );
document.write( "(6+1)^2+(6+2)^2=6^2+77<BR>\n" );
document.write( "7^2+8^2=36+77<BR>\n" );
document.write( "49+64=113<BR>\n" );
document.write( "113=113 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );