document.write( "Question 235375: A truck driver traveled at 40 mph for the first part of a 646-mile trip, then increased his speed to 58 mph for the rest of the trip. The entire trip took 13 hours. How many hours are traveled at 58 mph?
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Algebra.Com's Answer #173395 by Stitch(470)\"\" \"About 
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The Setup
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\n" ); document.write( "Equation 1: \"40%2AX+%2B+58%2AY+=+646\"
\n" ); document.write( "Equation 2: \"X+%2B+Y+=+13\"\r
\n" ); document.write( "\n" ); document.write( "Solution:
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\n" ); document.write( "Solve equation 2 for one of the variables. I picked X.
\n" ); document.write( "\"X+%2B+Y+=+13\" Rewrite
\n" ); document.write( "\"X+=+13+-+Y\"
\n" ); document.write( "Now plug (13 - Y) in for X in equation 1
\n" ); document.write( "\"40%2AX+%2B+58%2AY+=+646\"
\n" ); document.write( "\"40%2A%2813+-+Y%29+%2B+58%2AY+=+646\" Multiply the 40 by (13 - Y) and rewrite
\n" ); document.write( "\"520+-+40Y+%2B+58Y+=+646\" Combine like terms
\n" ); document.write( "\"520+%2B+18Y+=+646\" Subtract 520 from both sides
\n" ); document.write( "\"18Y+=+126\" Divide both sides by 18
\n" ); document.write( "\"Y+=+7\"
\n" ); document.write( "Now we know the the truck driver went 58mph for 7 hours.\r
\n" ); document.write( "\n" ); document.write( "Check Answer:
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\n" ); document.write( "Plug 7 into equation 2 for Y
\n" ); document.write( "\"X+%2B+Y+=+13\"
\n" ); document.write( "\"X+%2B+7+=+13\" Subtract 7 from both sides
\n" ); document.write( "\"X+=+6\"
\n" ); document.write( "Now go back to equation 1 and plug 7 in for Y, and use 6 for X.
\n" ); document.write( "\"40%2AX+%2B+58%2AY+=+646\"
\n" ); document.write( "\"40%2A6+%2B+58%2A7+=+646\" Simplify
\n" ); document.write( "\"240+%2B+406+=+646\"
\n" ); document.write( "\"646+=+646\"\r
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