document.write( "Question 235338: please SOLVE and CHECK this algebra problem : \"the perimeter of a rectangle is 420 inches.The width is 4 inches less than the length.What is the length of the rectangle?\" \n" ); document.write( "
Algebra.Com's Answer #173386 by Stitch(470)\"\" \"About 
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The perimeter of a rectangle is equal to 2L + 2W
\n" ); document.write( "Equation 1: \"2%2AL+%2B+2%2AW+=+420in\"
\n" ); document.write( "Equation 2: \"W+=+L+-+4in\"
\n" ); document.write( "Solution:
\n" ); document.write( "Plug L-4 into equation 1 for W
\n" ); document.write( "\"2%2AL+%2B+2%2AW+=+420in\"
\n" ); document.write( "\"2%2AL+%2B+2%2A%28L+-+4%29+=+420in\" rewrite the equation
\n" ); document.write( "\"2%2AL+%2B+2%2AL+-+8+=+420in\" Combine like terms
\n" ); document.write( "\"4%2AL+-+8+=+420in\" Add 8 to both sides
\n" ); document.write( "\"4%2AL+=+428in\" Divide both sides by 4
\n" ); document.write( "\"L+=+107in\"
\n" ); document.write( "The length of the rectangle is 107in.\r
\n" ); document.write( "\n" ); document.write( "Check your answer:
\n" ); document.write( "Plug 107 into equation 2 for L
\n" ); document.write( "\"W+=+L+-+4in\"
\n" ); document.write( "\"W+=+107+-+4in\"
\n" ); document.write( "\"W+=+103in\"
\n" ); document.write( "Now plug the answers for L and W into equation 1
\n" ); document.write( "\"2%2AL+%2B+2%2AW+=+420in\"
\n" ); document.write( "\"2%2A107+%2B+2%2A103+=+420in\"
\n" ); document.write( "\"214in+%2B+206in+=+420in\"
\n" ); document.write( "\"420in+=+420in\"
\n" ); document.write( "
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