document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235297>Question 235297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions: one containing 40% alcohol and another containing 70% alcohol.  How much of each should be used to obtain 80 liters of 49% solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173376 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A chemist has two solutions: one containing 40% alcohol and another containing 70% alcohol. How much of each should be used to obtain 80 liters of 49% solution.<BR>\n" );
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document.write( "Let x= liters of 40% alcohol<BR>\n" );
document.write( "then<BR>\n" );
document.write( "80-x = liters of 70% alcohol<BR>\n" );
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document.write( ".40x + .70(80-x) = .49(80)<BR>\n" );
document.write( ".40x + 56 - .70x = 39.2<BR>\n" );
document.write( "56 - .30x = 39.2<BR>\n" );
document.write( "-.30x = -16.8<BR>\n" );
document.write( "x = 56 liters of 40% alcohol<BR>\n" );
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document.write( "70% alcohol:<BR>\n" );
document.write( "80-x = 80-56 = 24 liters of 70% alcohol\r<BR>\n" );
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document.write( " </SPAN>\n" );
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