document.write( "Question 235145: The half-life of a certain radioactive substance is 15 years.
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document.write( "Suppose that at time t = 0, there are 29 g of the substance.
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document.write( "Then after t years, the number of grams of the substance remaining will be
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document.write( "How many grams of the substance will remain after 45 years?
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Algebra.Com's Answer #173364 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The half life formula \n" ); document.write( "A = Ao(2^(-t/h)) \n" ); document.write( "Where \n" ); document.write( "A = resulting amt after t yrs \n" ); document.write( "Ao = initial amt \n" ); document.write( "h = half-life of substance \n" ); document.write( ": \n" ); document.write( "The half-life of a certain radioactive substance is 15 years. \n" ); document.write( "Suppose that at time t = 0, there are 29 g of the substance. \n" ); document.write( "Then after t years, the number of grams of the substance remaining will be: \n" ); document.write( "A = 29(2^(-t/15)) \n" ); document.write( ": \n" ); document.write( "How many grams of the substance will remain after 45 years? \n" ); document.write( "A = 29(2^(-45/15)) \n" ); document.write( "A = 29(2^-3) \n" ); document.write( "A = 29*.125 \n" ); document.write( "A = 3.625 grams \n" ); document.write( " |