document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30600>Question 30600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the maxima and the minima to the nearest tenth of this equation,<BR>\n" );
document.write( "-x^4+3x^2+3;-5<= x <=5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17328 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the maxima and the minima to the nearest tenth of this equation,<BR>\n" );
document.write( "-x^4+3x^2+3;-5<= x <=5?<BR>\n" );
document.write( "DO YOU KNOW CALCULUS..PLEASE INFORM..THEN IT CAN BE EASILY DONE ...IF NOT .TRY THIS WAY...<BR>\n" );
document.write( "Y= -{(X^2)^2-2*(3/2)*(X^2)+(3/2)^2}+(3/2)^2<BR>\n" );
document.write( "=(9/4)-{X^2-1.5}^2<BR>\n" );
document.write( "SINCE (X^2-1.5)^2 IS ALWAYS POSITIVE ITS MINIMUM VALUE IS ZERO.<BR>\n" );
document.write( "S0 Y WILL BE MAXIMUM WHEN X^2=1.5..X=+ AND - SQUARE ROOT OF 1.5 WHICH IS IN THE GIVEN RANGE<BR>\n" );
document.write( "MAXIMUM VALUE OF Y IS 9/4. </SPAN>\n" );
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