document.write( "Question 235092: 3 over 7 minus the square root of 2
\n" ); document.write( "Okay so I multiplyed by the opposite, which would be 7 plus square root of 2 on both the deonominator and top.
\n" ); document.write( "I got 21 + 3 to the radical of 2 over 47
\n" ); document.write( "Did I do this right or am I totally wrong?
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Algebra.Com's Answer #173264 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
3 / (7-sqrt(2))\r
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\n" ); document.write( "\n" ); document.write( "To remove the square root from the denominator, multiply numerator and denominator by (7+sqrt(2)\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "3 * (7+sqrt(2)) / 49 - 2 which equals:\r
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\n" ); document.write( "\n" ); document.write( "21 + 3*sqrt(2) / 47\r
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\n" ); document.write( "\n" ); document.write( "If \"21 + 3 to the radical of 2 over 47\" is the same as \"21 + 3*sqrt(2)\" then you got it right.\r
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\n" ); document.write( "\n" ); document.write( "sqrt(2) looks like \"sqrt%282%29\" after going through the algebra.com formula generator.\r
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\n" ); document.write( "\n" ); document.write( "It's not 3 to the radical of 2.\r
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\n" ); document.write( "\n" ); document.write( "It would be 3 times the radical of 2.\r
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\n" ); document.write( "\n" ); document.write( "I would say it as 3 times the square root of 2.\r
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\n" ); document.write( "\n" ); document.write( "The answer would look like \"%2821+%2B+3%2Asqrt%282%29%29%2F47\"\r
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