document.write( "Question 30613: Solve each quadratic equation by factoring and applying the 0 product principle.
\n" ); document.write( "2x^2-x=1
\n" ); document.write( "answers= -5,2
\n" ); document.write( "3x^2-7x=0
\n" ); document.write( "answers= 0,7/3
\n" ); document.write( "Could someone please write out the steps for me?
\n" ); document.write( "Thank you! \n" ); document.write( "
Algebra.Com's Answer #17318 by Nate(3500)\"\" \"About 
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2x^2-x=1 original equation
\n" ); document.write( "2x^2-x-1=0 set the equation to zero
\n" ); document.write( "2x^2-2x+x-1=0 the product leading coefficient and the constant is -2 (two numbers that add up to -1 and are multiplied to get the -2 is: -2 and 1)
\n" ); document.write( "(2x^2-2x)+(x-1)=0 start to combine
\n" ); document.write( "2x(x-1)+1(x-1)=0 take out the factors
\n" ); document.write( "(2x+1)(x-1)=0 set them to zero
\n" ); document.write( "2x+1 = 0 ; 2x = -1 ; x = -1/2
\n" ); document.write( "x-1 = 0 ; x = 1
\n" ); document.write( "1 and (-1/2) are your answers
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\n" ); document.write( "3x^2-7x=0
\n" ); document.write( "x(3x-7)=0 set them to zero
\n" ); document.write( "x=0
\n" ); document.write( "3x-7=0 ; 3x=7 ; x=7/3
\n" ); document.write( "0 and (7/3) are the answers \n" ); document.write( "
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