document.write( "Question 234924: it is assumed that labour productivity of particular members in a factory can be described by a normal distribution with sigma=3.what is probability that a sample mean calculated for 9 randomly chosen workers differs from the population mean by more than 2 units?
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Algebra.Com's Answer #173175 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! it is assumed that labour productivity of particular members in a factory can be described by a normal distribution with sigma=3.what is probability that a sample mean calculated for 9 randomly chosen workers differs from the population mean by more than 2 units? \n" ); document.write( "----------------------------------- \n" ); document.write( "The std of the sample means is 3/sqrt(3). \n" ); document.write( "- \n" ); document.write( "Comment: You did not post a mean value for the population \n" ); document.write( "and I made the mistake of assuming it was 3. All the \n" ); document.write( "work I did is based on that assumption. \n" ); document.write( "Check your problem statement. Maybe that phrase \n" ); document.write( "\"more that 2 units\" refers to standard deviation \n" ); document.write( "units. \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "If x-bar differs from the mean by more that 2 units, \n" ); document.write( "x-bar is less than 1 or x-bar is greater than 5. \n" ); document.write( "------ \n" ); document.write( "z(1) = (1-3)/sqrt(9) = -2/3 \n" ); document.write( "z(5) = (5-3)/sqrt(9) = 2/3 \n" ); document.write( "----- \n" ); document.write( "P(x-bar < 1)= P(z < -2/3) = 0.2525 \n" ); document.write( "P(x-bar > 4)= P(z > 2/3) = 0.2525 \n" ); document.write( "---- \n" ); document.write( "Ans: 0.2525+0.2525 = 0.5050 \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |