document.write( "Question 234897: please help! no idea where to start on this one\r
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document.write( "The first apartment I rented was 32 years ago in Chicago. The rent was $250 a
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document.write( "month. If inflation has been more or less around 4% a year and the rent has gone up
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document.write( "according to the inflation. What do you think the rent for that apartment is today? \n" );
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Algebra.Com's Answer #173166 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 250 a month 32 years ago.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rent goes up 4% each year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "250 * (1.04)^32 = 877.0146867 today.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Inflation is the increase in price per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 4% per year, the rent is multiplied by 1.04 each year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first year the rent is $250 \n" ); document.write( "Second year the rent is $250 * 1.04 = $260.00 \n" ); document.write( "Third year the rent is $260.00 * 1.04 = $270.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You went up two years. \n" ); document.write( "The formula is $250 * (1.04)^n where n is the number of years. \n" ); document.write( "n = 2 \n" ); document.write( "250 * (1.04)^2 = $270.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When n = 32, the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "250 * (1.04)^32 = $877.0146867\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |