document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234919>Question 234919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of 40% and 80% acids must be mixed in order to make 20 liters of a 55% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173138 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of liters of 40% acid solution, then (20-x) = the number of liters of 80% acid solution. The sum of these is = 20 liters of 55% acid solution.<BR>\n" );
document.write( "This can be expressed algebraically, after converting the percentages to their decimal equivalents, as:<BR>\n" );
document.write( "0.4x+0.8(20-x) = 0.55(20) Simplify the left side.<BR>\n" );
document.write( "0.4x+16-0.8x = 11 Combine like-terms.<BR>\n" );
document.write( "-0.4x+16 = 11 Subtract 16 from both sides.<BR>\n" );
document.write( "-0.4x = -5 Divide both sides by -0.4<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x+=+12.5%29 ALIGN=MIDDLE  ALT=\"highlight%28x+=+12.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%2820-x%29+=+7.5%29 ALIGN=MIDDLE  ALT=\"highlight%28%2820-x%29+=+7.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You would need to mix 12.5 liters of 40% acid solution with 7.5 liters of 80% acid solution to obtain 20 liters of 55% acid soltion. </SPAN>\n" );
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