document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234780>Question 234780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jerome blends Brand A of coffee that sells for $9.50 a pound with Brand B of coffee that sells for $12.00 a pound. If the 45 pounds of blend sells for $10.50 a pound, how many pounds of each type of coffee did Jerome use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173111 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12x+9.50(45-x)=10.50*45<BR>\n" );
document.write( "12x+427.5-9.5x=472.5<BR>\n" );
document.write( "2.5x=472.5-427.5<BR>\n" );
document.write( "2.5x=45<BR>\n" );
document.write( "x=45/2.5<BR>\n" );
document.write( "x=18 pounds of the $12 coffee is used.<BR>\n" );
document.write( "45-18=27 pounds of the $9.50 coffee is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "12*18+9.5*27=10.50*45<BR>\n" );
document.write( "216+256.5=472.5<BR>\n" );
document.write( "472.5=472.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );