document.write( "Question 234808: the sum of two numbers is 13. one number is 1 more than twice the other. find the smaller number. \n" ); document.write( "
Algebra.Com's Answer #173100 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=13 OR X=13-Y \n" ); document.write( "X=2Y+1 \n" ); document.write( "13-Y=2Y+1 \n" ); document.write( "-Y-2Y=1-13 \n" ); document.write( "-3Y=-12 \n" ); document.write( "Y=-12/-3 \n" ); document.write( "Y=4 ANS. FOR THE SMALLER NUMBER. \n" ); document.write( "X+4=13 \n" ); document.write( "X=13-4 \n" ); document.write( "X=9 ANS. FOR THE LARGER NUMBER.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |