document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234753>Question 234753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 70% acid solution must be mixed with 30 gallons of a 24% solution to obtain a solution that is 60% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173095 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .70x+.24*30=.60(30+x)<BR>\n" );
document.write( ".70x+7.2=18+.6x<BR>\n" );
document.write( ".70x-.60x=18-7.2<BR>\n" );
document.write( ".1x=10.8<BR>\n" );
document.write( "x=10.8/.1<BR>\n" );
document.write( "x=108 gallons of 70% acid is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".70*108+.24*30=.60(30+108)<BR>\n" );
document.write( "75.6+7.2=.6*138<BR>\n" );
document.write( "82.8=82.8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );