document.write( "Question 234752: if john is twice as old as his son in 20 years the ratio of their ages will be 4:3 what is Johns sons current age? \n" ); document.write( "
Algebra.Com's Answer #173084 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If john is twice as old as his son in 20 years the ratio of their ages will be 4:3, \n" ); document.write( " what is John's son's current age? \n" ); document.write( ": \n" ); document.write( "let j = John's current age \n" ); document.write( "Let s = Son's current age \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "3(j+20) = 4(s+20) \n" ); document.write( "3j + 60 = 4s + 80 \n" ); document.write( "3j = 4s + 80 - 60 \n" ); document.write( "3j = 4s + 20 \n" ); document.write( ": \n" ); document.write( "It said,\"John is twice as old as his son\" \n" ); document.write( "j = 2s \n" ); document.write( "Substitute 2s of j in the above equation \n" ); document.write( "3(2s) = 4s + 20 \n" ); document.write( "6s = 4s + 20 \n" ); document.write( "6s - 4s = 20 \n" ); document.write( "2s = 20 \n" ); document.write( "s = 10 yrs is son's current age \n" ); document.write( "then \n" ); document.write( "2(10) = 20 yrs is John's present age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in 20 yrs \n" ); document.write( "40/30 = 4/3 \n" ); document.write( " |