document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234713>Question 234713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that $9000 is invested at an interest rate of 5.4% per year, compounded continuously What is the doubling time?\r<BR>\n" );
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document.write( "I know that the equation is Pe^rt, but i am not certain about what exactly to do. i have the general idea, i am just not getting it.\r<BR>\n" );
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document.write( "Please Help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173041 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose that $9000 is invested at an interest rate of 5.4% per year, compounded continuously What is the doubling time? <BR>\n" );
document.write( "I know that the equation is Pe^rt<BR>\n" );
document.write( "18000 = 9000e^(0.054t)<BR>\n" );
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document.write( "e^(0.054t) = 2<BR>\n" );
document.write( "Take the natural log to get:<BR>\n" );
document.write( "0.054t = ln(2)<BR>\n" );
document.write( "t = [ln(2)]/0.054<BR>\n" );
document.write( "t = 12.836.. years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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