document.write( "Question 234697: A boy leaves on a bicycle trip at the rate of 8 mph. One hour later the father, realizing that his son forgot his camping gear, sets out by car. How fast must the father drive to overtake the boy in 15 minutes?\r
\n" ); document.write( "\n" ); document.write( "D= x
\n" ); document.write( "R= 8mph
\n" ); document.write( "T= 1hr + 15min.-----> 75min.\r
\n" ); document.write( "\n" ); document.write( "8x75min. = 600 mph. \r
\n" ); document.write( "\n" ); document.write( "This is what I've tried doing.
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Algebra.Com's Answer #173029 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "After the boy has been gone for 1 hour at 8 miles per hour, he will be 8 miles from home. If Dad catches him in 15 minutes, then he will have traveled another 15 minutes at 8 miles per hour. Since 15 minutes is one-quarter hour, he will have gone another 8 divided by 4 = 2 miles. The 8 miles the boy traveled in the first hour plus the 2 miles he traveled in the following 15 minutes makes a total of 10 miles -- and that is the distance Dad has to travel in that 15 minutes. 10 miles per 15 minutes times 4/4 = 40 miles per 60 minutes = 40 miles per hour.\r
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