document.write( "Question 234636: If Leah is 6 years older than sue and john is 5 years older than Leah and the total of their ages is 41. Then how old is sue?\r
\n" ); document.write( "\n" ); document.write( "please show me how to set up the equation for this
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Algebra.Com's Answer #172996 by Stitch(470)\"\" \"About 
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Leah's age = A
\n" ); document.write( "Sue's age = B
\n" ); document.write( "John age = C\r
\n" ); document.write( "\n" ); document.write( "Equation 1: \"A+%2B+B+%2B+C+=+41\"
\n" ); document.write( "Leah is 6 years older than so, that gives us equation 2.
\n" ); document.write( "Equation 2: \"A+=+B+%2B+6\"
\n" ); document.write( "John is 5 years older than Leah, that gives us equation 3.
\n" ); document.write( "\"C+=+A+%2B+5\"
\n" ); document.write( "You can rewrite John's age in terms of Sue.
\n" ); document.write( "C = A + 5 & A = B + 6
\n" ); document.write( "There fore C = B + 6 + 5
\n" ); document.write( "Substitute the new value for C into equation 1.
\n" ); document.write( "A + B + C = 41
\n" ); document.write( "\"A+%2B+B+%2B+B+%2B+6+%2B+5+=+41\" Then substitute equation 2 in for A in equation 1.
\n" ); document.write( "A = B + 6
\n" ); document.write( "\"B+%2B+6+%2B+B+%2B+B+%2B+6+%2B+5+=+41\" Combine like terms
\n" ); document.write( "\"3B+%2B+17+=+41\" Substract 17 from both sides
\n" ); document.write( "\"3B+=+24\" Divide both sides by 3
\n" ); document.write( "\"B+=+8\"
\n" ); document.write( "Sue is 8
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