document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234633>Question 234633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man has 35 coins consisting of dimes and quarters.  The total value is $5.15.  How many of each coin does he have?  I know that there are 24 dimes and 11 quarters (working it backwards) but I can't figure out what the equation should be to solve for this problem.  Can ANYONE please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172992 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man has 35 coins consisting of dimes and quarters. The total value is $5.15. How many of each coin does he have?<BR>\n" );
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document.write( "Quantity Equation: d + q = 35<BR>\n" );
document.write( "Value Equation:::10d+ 25q = 5l5 cents<BR>\n" );
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document.write( "Multiply thru the Quantity Equation by 10 to get:<BR>\n" );
document.write( "10d + 10q = 350<BR>\n" );
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document.write( "Subtract that from the Value Equation and solve for \"q\":<BR>\n" );
document.write( "15q = 165<BR>\n" );
document.write( "q = 11 (# of quarters)<BR>\n" );
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document.write( "Since d+q = 35, d+11 = 35 ; d = 24 (# of dimes)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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