document.write( "Question 234575: i need help with two problems?\r
\n" ); document.write( "\n" ); document.write( "1/X^2+3x-10 + 1/x-6 all over 1/x-5 - 1/X^2-8x+12 that is my first one\r
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\n" ); document.write( "\n" ); document.write( "the second one is 5/x + 3/2x all over 1/3x + 1/4x\r
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Algebra.Com's Answer #172960 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1/X^2+3x-10 + 1/x-6 all over 1/x-5 - 1/X^2-8x+12 that is my first on=5)(xe
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\n" ); document.write( "The lcd of the left side and of the right side are the
\n" ); document.write( "same and they cancel leaving:\r
\n" ); document.write( "\n" ); document.write( "[(x-6)+(x^2+3x-10] over [x^2-8x+12-(x-5)]
\n" ); document.write( "Simplify:
\n" ); document.write( "x^2+4x-16 over x^2-9x+17
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\n" ); document.write( "\n" ); document.write( "the second one is 5/x + 3/2x all over 1/3x + 1/4x
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\n" ); document.write( "(10x+3x)/2x^2 all over (4x+3x)/12x^2
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\n" ); document.write( "13/2x over 7/12x
\n" ); document.write( "Invert the denominator and multiply
\n" ); document.write( "(13/2x)(12x/7)
\n" ); document.write( "(13*6)/7
\n" ); document.write( "78/7
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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