document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234562>Question 234562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify \r<BR>\n" );
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document.write( "3 over a plus 1 divided by 3 over a minus 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172939 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3/a) + (1/3)/(3/a - 1) =\r<BR>\n" );
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document.write( "I would simplify the left side fraction first and then add everything together using the same rules for regular fractions..\r<BR>\n" );
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document.write( "(1/3)/(3/a - 1) becomes 1/(3a - 3).\r<BR>\n" );
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document.write( "We now have (3/a) + 1/(3a - 3) = \r<BR>\n" );
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document.write( "Apply the same rules for regular fractions.\r<BR>\n" );
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document.write( "The denominators are different.  This means we need the LCD.\r<BR>\n" );
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document.write( "LCD = a(3a - 3)\r<BR>\n" );
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document.write( "After doing the math, I got (10a - 9)/a(3a - 3) </SPAN>\n" );
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