document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234506>Question 234506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help prove: 1-(cos(beta)-sin(beta)^2^=sin(2beta) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172915 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1-(cos(beta)-sin(beta)^2^=sin(2beta)<BR>\n" );
document.write( "1 - (cos^2(b) - 2sin(b)cos(b) + sin^2(b)) = 2sin(b)cos(b)<BR>\n" );
document.write( "All angular arguments are the same, so assume it's b (saves typing)<BR>\n" );
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document.write( "1 - cos^2 + 2sincos - sin^2 = 2sincos<BR>\n" );
document.write( "1 - cos^2 - sin^2 = 0<BR>\n" );
document.write( "sin^2 + cos^2 = 1  We all know that, right? So it's true. </SPAN>\n" );
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