document.write( "Question 234505: investment of 4000 in 3 months with interest of 6.1 what was the earned amount? \n" ); document.write( "
Algebra.Com's Answer #172896 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
P=(1+r/n)^t/n
\n" ); document.write( "Where P=principle, r=rate (in decimal form),n=number of periods per year. t=number of years.
\n" ); document.write( "4,000(1+.061/4)^1/4
\n" ); document.write( "4,000(1+.01525)^.25
\n" ); document.write( "4,000(1.01525)^.25
\n" ); document.write( "4,000*1.00379=$4,015.16 ans.
\n" ); document.write( "
\n" );