document.write( "Question 234483: what is product of the divisors of 1000 (including 1 and 1000)?\r
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Algebra.Com's Answer #172885 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"1000+=+2%5E3%2A5%5E3\" has only the prime divisors \"2\" and \"5\".\r\n" );
document.write( "Every divisor of \"1000\" is therefore of the form \"2%5Ep%2A5%5Eq\",\r\n" );
document.write( "where \"p\" and \"q\" are elements of {0,1,2,3}.  Since there\r\n" );
document.write( "are \"4\" choices for \"p\" and \"4\" choices for \"q\", there are \"16\"\r\n" );
document.write( "divisors of \"1000\".  That isn't necessary to know.  But\r\n" );
document.write( "in the product of all \"16\" divisors of \"1000\", \"2%5E0%2A2%5E1%2A2%5E2%2A2%5E3\"\r\n" );
document.write( "or \"2%5E6\", and \"5%5E0%2A5%5E1%2A5%5E2%2A5%5E3\" or \"5%5E6\" occur exactly \"4\" times each.\r\n" );
document.write( "Since \"2%5E6\" and \"5%5E6\" both occur \"4\" times each in the product\r\n" );
document.write( "of all divisors, the product of the divisors must be\r\n" );
document.write( "\"%282%5E6%29%5E4%2A%285%5E6%29%5E4+=+2%5E24%2A5%5E24+=+10%5E24\", choice a)\r\n" );
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document.write( "Edwin
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