document.write( "Question 234400: Maria added white vinegar solution of acetic acid in water. There are 2 strengths of white vinegar-a 5% solution and a 10% solution. How many millilitres of each solution must she mix to make 50mL of a 9% vinegar solution? \n" ); document.write( "
Algebra.Com's Answer #172836 by josmiceli(19441)\"\" \"About 
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Let \"a\" = ml of 5% solution to be added
\n" ); document.write( "Let \"b\" = ml of 10% solution to be added
\n" ); document.write( "given:
\n" ); document.write( "Total ml of final solution = \"50\" ml
\n" ); document.write( "Ml of acetic acid in final solution, \".09%2A50+=+4.5\" ml
\n" ); document.write( "------------------------------------------------
\n" ); document.write( "In words:
\n" ); document.write( "( acetic acid in 5% solution) + (acetic acid in 10% solution)/ (total ml of solution) = 9%
\n" ); document.write( "(1) \"%28.05a+%2B+.1b%29%2F50+=+.09\"
\n" ); document.write( "(2) \"a+%2B+b+=+50\"
\n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "Multiply both sides of (1) by \"50\"
\n" ); document.write( "(1) \".05a+%2B+.1b+=+4.5\"
\n" ); document.write( "(1) \"5a+%2B+10b+=+450\"
\n" ); document.write( "Now multiply both sides of (2) by \"5\" and subtract from (1)
\n" ); document.write( "(1) \"5a+%2B+10b+=+450\"
\n" ); document.write( "(2) \"-5a+-+5b+=+-250\"
\n" ); document.write( "\"5b+=+200\"
\n" ); document.write( "\"b+=+40\"
\n" ); document.write( "and, since
\n" ); document.write( "\"a+%2B+b+=+50\"
\n" ); document.write( "\"a+=+50+-+40\"
\n" ); document.write( "\"a+=+10\"
\n" ); document.write( "10 ml of 5% solution and 40 ml of 10% solution are needed
\n" ); document.write( "check answer:
\n" ); document.write( "(1) \".05a+%2B+.1b%29%2F50+=+.09\"
\n" ); document.write( "(1) \".05%2A10+%2B+.1%2A40%29%2F50+=+.09\"
\n" ); document.write( "\"%28.5+%2B+4%29%2F50+=+.09\"
\n" ); document.write( "\"4.5%2F50+=+.09\"
\n" ); document.write( "\".09+=+.09\"
\n" ); document.write( "OK
\n" ); document.write( "
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