document.write( "Question 234375: the attendance at a school concert was 578. admission cost $2.00 for adults and $1.50 for children. the receipts for the concert were $985.00. how many adults and how many children attended the concert? \n" ); document.write( "
| Algebra.Com's Answer #172835 by checkley77(12844)      You can put this solution on YOUR website! A+C=578 OR A=578-C \n" ); document.write( "2A+1.5C=985 \n" ); document.write( "2(578-C)+1.5C=985 \n" ); document.write( "1156-2C+1.5C=985 \n" ); document.write( "-.5C=985-1156 \n" ); document.write( "-.5C=-171 \n" ); document.write( "C=-171/-.5 \n" ); document.write( "C=342 CHILDREN'S TICKETS WERE SOLD. \n" ); document.write( "A=578-342=236 ADULT TICKETS WERE SOLD. \n" ); document.write( "PROOF: \n" ); document.write( "2*236+1.5*342=985 \n" ); document.write( "472+513=985 \n" ); document.write( "985=985 \n" ); document.write( " |