document.write( "Question 234326: Can you help\r
\n" );
document.write( "\n" );
document.write( "solve
\n" );
document.write( "3v^2 + 4v - 1 = 0
\n" );
document.write( "please find all solutions real and imaginary \n" );
document.write( "
Algebra.Com's Answer #172804 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 3v^2 + 4v - 1 = 0 \n" ); document.write( " \n" ); document.write( "v=(-4+-sqrt[4^2-4*3*-1])/2*3 \n" ); document.write( "v=(-4+-sqrt[16+12)/6 \n" ); document.write( "v=(-4+-sqrt28)/6 \n" ); document.write( "v=(-4+-5.2915)/6 \n" ); document.write( "v=(-4+5.2915)/6 \n" ); document.write( "v=1.2915/6 \n" ); document.write( "v=.215 ans. \n" ); document.write( "v=(-4-5.2915)/6 \n" ); document.write( "v=-9.2915/6 \n" ); document.write( "v=-1.549 ans. \n" ); document.write( " |