document.write( "Question 234331: a boy is twice as old as his brother , 4 year a ago he was 3 times as old as his brother. find thier present ages \n" ); document.write( "
Algebra.Com's Answer #172798 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
boy=2x age now
\n" ); document.write( "brother=x age now
\n" ); document.write( "2x-4=3(x-4)
\n" ); document.write( "2x-4=3x-12
\n" ); document.write( "2x-3x=-12+4
\n" ); document.write( "-x=-8
\n" ); document.write( "x=8 is the age of the brother now.
\n" ); document.write( "boy=2*8=16 the age of the boy now.
\n" ); document.write( "Proof:
\n" ); document.write( "2*8-4=3(8-4)
\n" ); document.write( "16-4=3*4
\n" ); document.write( "12=12
\n" ); document.write( "
\n" );