document.write( "Question 234331: a boy is twice as old as his brother , 4 year a ago he was 3 times as old as his brother. find thier present ages \n" ); document.write( "
Algebra.Com's Answer #172798 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! boy=2x age now \n" ); document.write( "brother=x age now \n" ); document.write( "2x-4=3(x-4) \n" ); document.write( "2x-4=3x-12 \n" ); document.write( "2x-3x=-12+4 \n" ); document.write( "-x=-8 \n" ); document.write( "x=8 is the age of the brother now. \n" ); document.write( "boy=2*8=16 the age of the boy now. \n" ); document.write( "Proof: \n" ); document.write( "2*8-4=3(8-4) \n" ); document.write( "16-4=3*4 \n" ); document.write( "12=12 \n" ); document.write( " |