document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234293>Question 234293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of the solutions do I need to use when one container has 40% and another has 100% and 50% is needed for one gallon?I came up with a huge number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172773 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much of the solutions do I need to use when one container has 40% and another has 100% and 50% is needed for one gallon?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "0.40x + 1(1-x) = 0.50(1)<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40x + 100(1-x) = 50<BR>\n" );
document.write( "40x + 100 -100x = 50<BR>\n" );
document.write( "-60x = -50<BR>\n" );
document.write( "x = 5/6 gal. (amount of 40% solution needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1-x = 1-(5/6) = 1/6 gal. (amount of 100% solution needed in the mixture)<BR>\n" );
document.write( "===========================================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );