document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30590>Question 30590</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations using the substitution method.<BR>\n" );
document.write( "3x + y = 2<BR>\n" );
document.write( "2x – y = 3<BR>\n" );
document.write( "This is what I cam up with, but It doesn't seem correct.<BR>\n" );
document.write( "3x + y =2<BR>\n" );
document.write( "Isolate the y by sub. 3x from both sides<BR>\n" );
document.write( "3x-3x + y =3x +2<BR>\n" );
document.write( "substitute 3x + 2 for y<BR>\n" );
document.write( "2x - 3x + 2=3<BR>\n" );
document.write( "This is where I get lost, not sure if this is even correct<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17277 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You know what you're doing, but you have to look it over really well...<BR>\n" );
document.write( "Lets look at your problem:<BR>\n" );
document.write( "3x-3x + y =3x +2 ...... the 3x should be negative because you subtracted it<BR>\n" );
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document.write( "Know, lets begin:<BR>\n" );
document.write( "3x + y = 2 original equation<BR>\n" );
document.write( "y= -3x + 2 sub. 3x<BR>\n" );
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document.write( "2x – y = 3 original equation<BR>\n" );
document.write( "2x - (-3x + 2) = 3 substitute<BR>\n" );
document.write( "2x + 3x - 2 = 3 distribute the negative one<BR>\n" );
document.write( "5x = 5 simplify<BR>\n" );
document.write( "x=1<BR>\n" );
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document.write( "know, lets plug 1 for x in one of the equations<BR>\n" );
document.write( "3x + y = 2 orginal equation<BR>\n" );
document.write( "3 + y = 2<BR>\n" );
document.write( "y= -1\r<BR>\n" );
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