document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234289>Question 234289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem:\r<BR>\n" );
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document.write( "Find three consecutive odd integers such that three times the second minus the third is 17 more than the first.\r<BR>\n" );
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document.write( "----Thank you =) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172768 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that three times the second minus the third is 17 more than the first. <BR>\n" );
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document.write( "1st: 2x-1<BR>\n" );
document.write( "2nd: 2x+1<BR>\n" );
document.write( "3rd: 2x+3<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3(2x+1)-(2x+3) = (2x-1)+17<BR>\n" );
document.write( "4x = 2x+16<BR>\n" );
document.write( "2x = 16<BR>\n" );
document.write( "x = 8<BR>\n" );
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document.write( "1st: 2x-1 = 15<BR>\n" );
document.write( "2nd: 17<BR>\n" );
document.write( "3rd: 19<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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