document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234204>Question 234204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a women travels one mile due north, then two miles due east, then three miles due north again, and then once more east for 4 miles. how far is she from her starting point? (it is less than 5+ square root 5 miles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172748 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> She is 4 miles north & 6 miles east of her starting location.<BR>\n" );
document.write( "Thus you have a right triangle with sides of 4 & 6 miles and need to find the hypotenuse.<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "4^2+6^2=c^2<BR>\n" );
document.write( "16+36=c^2<BR>\n" );
document.write( "52=c^2<BR>\n" );
document.write( "c=sqrt52<BR>\n" );
document.write( "c=7.211 miles is her distance from her starting point.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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