document.write( "Question 234211: x+3greather than or equal to 2x+1 \n" ); document.write( "
Algebra.Com's Answer #172742 by checkley77(12844)\"\" \"About 
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x+3>=2x+1
\n" ); document.write( "x-2x>=1-3
\n" ); document.write( "-x>=-2
\n" ); document.write( "x<=-2/-1 Note: when dividing by a negative value the > sign changes to a < sign.
\n" ); document.write( "x<=2 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "Let x=1.9
\n" ); document.write( "1.9+3>=2*1.9+1
\n" ); document.write( "4.9>=3.8+1
\n" ); document.write( "4.9>=4.8
\n" ); document.write( "
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