document.write( "Question 234235: #4 EllEN WISHES TO MIX CANDY WORTH $1.92 PER POUND WITH CANDY WORTH $3.11 PER POUND TO FORM 36 POUNDS OF A MIXTURE WORTH $2.48 PER POUND. HOW MANY POUNDS OF THE MORE EXPENSIVE CANDY SHOULD SHE USE? \n" ); document.write( "

Algebra.Com's Answer #172740 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Is there some reason you feel the need to SHOUT? Typing in ALL CAPS is the electronic equivalent of shouting, and is therefore both annoying and rude. Please stop.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let

represent the number of pounds of $3.11 per-pound candy. Since there are to be a total of 36 pounds in the final mixture, the number of pounds of $1.92 per-pound candy must be:

.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If there are

pounds of candy that cost $3.11, then the total cost of that part of the mixture must be

. Likewise the total cost of the less expensive part of the mixture must be

. And finally, the total cost of the overall mixture must be $2.48 times 36. The sum of the costs of the two kinds of candy must be the total cost of the mixture, so:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Just solve for

.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );