document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234222>Question 234222</A>: <I><SPAN STYLE=\"word-break: break-all;\">  a rectangle is 2 feet long and 1.5 feet wide,, what is the distance if you measure it diagonally? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172730 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> These 2 sides 2 ft. & 1.5 ft. along with the diagonal of the rectangle form a right triangle.<BR>\n" );
document.write( "Thus we have the formula for the 3 sides of a right triangle:<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "2^2+1.5^2=c^2<BR>\n" );
document.write( "4+2.25=c^2<BR>\n" );
document.write( "c^2=6.25<BR>\n" );
document.write( "c=sqrt6.25<BR>\n" );
document.write( "c=2.5 ft. ans. for the length of the long side (hypotenuse) of the triangle and the diagonal of the rectangle.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2^2+1.5^2=2.5^2<BR>\n" );
document.write( "4+2.25=6.25<BR>\n" );
document.write( "6.25=6.25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );