document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234117>Question 234117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> TRIGONOMETRIC FUNCTIONS<BR>\n" );
document.write( "1.Given that sin0=4/5 and 0 lies in quadrant ll,find the following value, cos 0<BR>\n" );
document.write( "2.Given that sin0=3/5 and 0 lies in quadrant ll,find the following value,sec 0<BR>\n" );
document.write( "3.Given that sin=-1/2 and 0 lies in quadrant lV,find the following value,cos 0<BR>\n" );
document.write( "4.Given that sin0=-1/2 and 0 lies in quadrant lV, find the following value,tan 0\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172682 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> BIG TIP: Post one question at a time or else no one will reply. <BR>\n" );
document.write( "1.Given that sin0=4/5 and 0 lies in quadrant ll,find the following value, cos 0. <BR>\n" );
document.write( "The first thing to know is that the sine function is positive in quadrant 2 but the cosine function is negative in that quadrant. <BR>\n" );
document.write( "Also, sine = opposite/hypotense and cosine = adjacent/hypotenuse. <BR>\n" );
document.write( "So, sin (0) = 4/5 means that the opposite side of this right triangle in quadrant 2 is 4 and its hypotenuse is 5. We now use the Pythagorean Theorem to find the other leg of the right triangle. <BR>\n" );
document.write( "(4)^2 + (leg)^2 = (5)^2 <BR>\n" );
document.write( "16 + (leg)^2 = 25 <BR>\n" );
document.write( "(leg)^2 = 25 - 16 <BR>\n" );
document.write( "(leg)^2 = 9 <BR>\n" );
document.write( "leg = 3 <BR>\n" );
document.write( "Now, that we know the other leg of the right triangle is 3, we use that information to find cos (0). <BR>\n" );
document.write( "Like I said above, cosine = adjacent/hypotenuse. <BR>\n" );
document.write( "Then, cos(0) = 3/5. <BR>\n" );
document.write( "However, since cosine is negative in quadrant 2, the answer is cos(0) = -3/5 <BR>\n" );
document.write( "Follow this same logic to answer the rest of your questions or post one question at a time. <BR>\n" );
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