document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234073>Question 234073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please explain how to solve for S in this problem, it's been a very long time since I've had to do problems of this nature. Thanks \r<BR>\n" );
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document.write( "2[s+3(s-1)]=18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172638 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> work your way out of thr parentheses and brackets first<BR>\n" );
document.write( "2[s+3(s-1)]=18<BR>\n" );
document.write( "2[s+3s-3]=18<BR>\n" );
document.write( "2[4s-3]=18<BR>\n" );
document.write( "8s-6=18<BR>\n" );
document.write( "add 6 to both sides<BR>\n" );
document.write( "8s=24<BR>\n" );
document.write( "s=3 </SPAN>\n" );
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