document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=233885>Question 233885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a question regarding a previous question that was answered.  It's under question #144072: \r<BR>\n" );
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document.write( "Q:Solve by factoring.<BR>\n" );
document.write( "The radius of a circle is increased by 3 in., which increases the area by 100 in^2. Find the radius of the original circle. Round to the nearest hundredth.<BR>\n" );
document.write( "Please answer.This question is from textbook Beginning Algebra with Applications\r<BR>\n" );
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document.write( "The answer was given as:\r<BR>\n" );
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document.write( "1. pi*r^2=A original\r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "2. pi*(r+3)^2=A+100 new \r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "3. pi(r^2+6r+9)=A+100\r<BR>\n" );
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document.write( "(this is clear)  <BR>\n" );
document.write( "4. pi(r^2+6r+9)-100=A\r<BR>\n" );
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document.write( "(this is clear) <BR>\n" );
document.write( "5. pi(r^2+6r+9)-100=pi*r^2\r<BR>\n" );
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document.write( "(please explain this step?  I don't understand how the transition took place from moving the \"pi\" from the front to placing it behind the 100 in the parentheses)? Please write out the step?<BR>\n" );
document.write( "6. r^2+6r+9-(100/pi)=r^2\r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "7. 6r+9-31.83=0\r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "8. 6r=22.83\r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "9. r=3.81\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #172575 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=172575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5. pi(r^2+6r+9)-100=pi*r^2 <BR>\n" );
document.write( "(please explain this step? I don't understand how the transition took place from moving the \"pi\" from the front to placing it behind the 100 in the parentheses)? Please write out the step?<BR>\n" );
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document.write( "The left side is the area after r is increased by 3 to (r+3).  Subtracting the 100 makes it equal to the area when the radius was still r.<BR>\n" );
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document.write( "6. r^2+6r+9-(100/pi)=r^2 \r<BR>\n" );
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document.write( "(this is clear)<BR>\n" );
document.write( "7. 6r+9-31.83=0 <BR>\n" );
document.write( "(this is clear)<BR>\n" );
document.write( "8. 6r=22.83 <BR>\n" );
document.write( "(this is clear)<BR>\n" );
document.write( "9. r=3.81  </SPAN>\n" );
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